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On March 27, 2004, the United States successfully tested the hypersonic X-43A scramjet, which flew at Mach 7.0 (seven times the speed of sound) for 11 seconds. (A scramjet gets its oxygen directly from the air, rather than from fuel.) For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Swim competition. Part A At this rate, how many minutes would it take such a scramjet to carry passengers the approximately 5000 kmkm from San Francisco to New York? (Use 331 m/sm/s for the speed of soun

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Answer:

Explanation:

Speed of sound = 331 m /s

speed of jet = 7 .00 Mach = 7 times speed of sound

= 7 x 331 = 2317 m /s

distance to be covered = 5000 x 1000 = 5 x 10⁶ m

Time taken = distance / speed of jet

= 5 x 10⁶ / 2317

= 2.158 x 10³ s

= 35.96 minutes .

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