Answer:
Let AB be the height of the building and B be the base as shown in the figure.
Using Pythagoras Theorem,
[tex]AC^{2} =AB^{2} +BC^{2} \\or, 22^{2}= AB^{2}+ 6^{2} \\or, 484 = AB^{2} +36\\or, AB^{2} = 448\\or, AB = 8\sqrt{7} feet\\So, the ladder reaches 8\sqrt{7} feet far from the building[/tex]
