Answer:
[tex]y=\frac{1}{3}[/tex]
Step-by-step explanation:
Subtract [tex]7[/tex] from both sides of the equation:
[tex]-4y+7=35y-6[/tex]
[tex]-4y+7[/tex][tex]-7=35y-6[/tex][tex]-7[/tex]
Simplify:
[tex]-4y+7[/tex][tex]-7=35y-6-7[/tex]
[tex]-4y=35y-6-7[/tex]
[tex]-4y=35y[/tex][tex]-6[/tex][tex]-7[/tex]
[tex]-4=35y[/tex][tex]-13[/tex]
[tex]-4y=35y-13[/tex]
Subtract [tex]35y[/tex] from both sides of the equation:
[tex]-4y=35y-13[/tex]
[tex]-4y[/tex][tex]-35y=35y-13[/tex][tex]-35y[/tex]
Simplify:
[tex]-4[/tex][tex]-35y=35y-13-35y[/tex]
[tex]-39y=35y-13-35y[/tex]
[tex]-39y=35y-13[/tex][tex]-35y[/tex]
[tex]-39y=-13[/tex]
[tex]-39y=-13[/tex]
Divide both sides of the equation by the same term:
[tex]-39y=-13[/tex]
[tex]\frac{-39y}{-39} =\frac{-13}{-39}[/tex]
Simplify:
- Cancel terms that are in both the numerator and denominator:
[tex]\frac{-39y}{-39} =\frac{-13}{-39}[/tex]
[tex]y=\frac{-13}{-39}[/tex]
[tex]y=\frac{-13}{-39}[/tex]
[tex]y=\frac{1}{3}[/tex]
