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Studies indicate that about 10 percent of polar bears weigh more than 1,000 pounds. A biologist studying the bears thinks that percent might be too high. From a random sample of polar bears, the biologist found only 8 percent of the sample weighing over 1,000 pounds. Which of the following is the most appropriate method for the biologist’s study?
A one-sample z
-test for a sample proportion
A one-sample z -test for a sample proportion

A one-sample z
-test for a population proportion
A one-sample z -test for a population proportion

A one-sample z
-test for a difference in population proportions
A one-sample z -test for a difference in population proportions

A two-sample z
-test for a difference in sample proportions
A two-sample z -test for a difference in sample proportions

A two-sample z
-test for a difference in population proportions

Respuesta :

Answer: B) A one sample Z test for a population proportion

Step-by-step explanation: Trust me bro.

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The correct statement should be "A one-sample z -test for a sample proportion".

Given information:

About 10 percent of polar bears weigh more than 1,000 pounds.

From a random sample of polar bears, the biologist found only 8 percent of the sample weighing over 1,000 pounds.

Based on the give information, the null hypothesis will be,

[tex]H_0\geq0.1[/tex]

Ans, the alternate hypothesis will be,

[tex]H_a<0.1[/tex]

So, we can say that the test is a left tailed or oriented.

Therefore, the correct statement should be "A one-sample z -test for a sample proportion".

For more details, refer to the link:

https://brainly.com/question/4233886

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