Answer:
His average speed for the rest of the journey was of 48mph.
Step-by-step explanation:
We use the following relation to solve this question:
[tex]v = \frac{d}{t}[/tex]
In which v is the velocity, d is the distance and t is the time.
First 32 miles at an average speed of 64mph.
So the time for these 32 miles is:
[tex]64 = \frac{32}{t}[/tex]
[tex]64t = 32[/tex]
[tex]t = \frac{32}{64}[/tex]
[tex]t = 0.5[/tex]
Rest of the trip:
200 - 32 = 168 miles in 4 - 0.5 = 3.5 hours. So the average speed is of:
[tex]v = \frac{d}{t} = \frac{168}{3.5} = 48[/tex]
His average speed for the rest of the journey was of 48mph.
