What is the result when we simplify the expression ( 1 + 1 x ) ( 1 − 2 x + 1 ) ( 1 + 2 x − 1 ) ( 1 + 1 x ) ( 1 − 2 x + 1 ) ( 1 + 2 x − 1 ) ?

Respuesta :

Answer:

[tex]4x^2\left(x+1\right)^2\left(-2x+2\right)^2[/tex]

Step-by-step explanation:

[tex]\left(1+1\cdot \:x\right)\left(1-2x+1\right)\left(1+2x-1\right)\left(1+1\cdot \:x\right)\left(1-2x+1\right)\left(1+2x-1\right)[/tex]

[tex]=\left(1+1\cdot \:x\right)\left(1+2x-1\right)\left(1+1\cdot \:x\right)\left(1-2x+1\right)^{1+1}\left(1+2x-1\right)[/tex]

[tex]=\left(1+2x-1\right)\left(1+1\cdot \:x\right)^{1+1}\left(1-2x+1\right)^2\left(1+2x-1\right)[/tex]

[tex]=\left(1+2x-1\right)\left(1+1\cdot \:x\right)^{1+1}\left(1-2x+1\right)^2\left(1+2x-1\right)[/tex]

[tex]=\left(1+2x-1\right)\left(1+1\cdot \:x\right)^2\left(1-2x+1\right)^2\left(1+2x-1\right)[/tex]

[tex]=\left(1+1\cdot \:x\right)^2\left(1-2x+1\right)^2\left(1+2x-1\right)^{1+1}[/tex]

[tex]=\left(x+1\right)^2\left(-2x+1+1\right)^2\left(2x+1-1\right)^2[/tex]

[tex]=\left(x+1\right)^2\left(-2x+2\right)^2\left(2x+1-1\right)^2[/tex]

[tex]=2^2x^2\left(x+1\right)^2\left(-2x+2\right)^2[/tex]

[tex]=4x^2\left(x+1\right)^2\left(-2x+2\right)^2[/tex]

Hope I helped you!

Success!