Answer:
a) 18.38
b) 4918.38
c) 18.44
d) 4936.82
e) 18.51
f) 4955.33
Step-by-step explanation:
Given
A [tex]= 4900[/tex]
r [tex]= \frac{1.5}{100} =0.015[/tex]
m [tex]= 4[/tex]
a)
I1
[tex]= 4900 *( 1 +\frac{0.015}{4})^{4 *\frac{3}{12}} -4900\\= 4918.38-4900\\= 18.38[/tex]
b) [tex]4918.38[/tex]
c)
[tex]= 4918.38 *( 1 +\frac{0.015}{4})^{4 *\frac{3}{12}} -4918.38\\= 4936.82-4918.38\\= 18.44[/tex]
d) [tex]4936.82[/tex]
e)
[tex]= 4936.82 *( 1 +\frac{0.015}{4})^{4 *\frac{3}{12}} -4936.82\\= 4955.33-4936.82\\= 18.51[/tex]
f) [tex]4955.33[/tex]
