A combined circuit has two resistors in parallel (34.0 ohms and 41.0 ohms) and another in series (15.0 ohms). If the power source is 9.0 volts, what will the current be?
I need to know the answer and exactly how the whole thing because I don't understand
current equals 0.09 A
... you add the the resistance of 41 and 34 making equalsthem 1 series resistor, then you add the sum wid 15 ohm.
therefore you devide 9 volts by dat 100 ohm sum to get current, dear
