Respuesta :
Answer:
The value of x = - 1 and 2 double root of this function
Step-by-step explanation:
we need to find the value of x which double root of [tex]f(x)=x^{3} -3x-2[/tex]
If we replace x with -2 then
[tex]f(-2)=(-2)^{3} -3(-2)-2 = -8+6-2 =-4[/tex]
If we replace x with -1 then
[tex]f(-1)=(-1)^{3} -3(-1)-2 = -1+3-2 =0[/tex]
If we replace x with 1 then
[tex]f(1)=(1)^{3} -3(1)-2 = 1-3-2 =-4[/tex]
If we replace x with 2 then
[tex]f(2)=(2)^{3} -3(2)-2 = 8-6-2 =0[/tex]
Hence, the value of x = - 1 and 2 double root of this function
