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The circle below is centered at (-3, 2) and has a radius of 3. What is its
equation?
A. (x-3)2 +(- 2)2 = 9
B. (x+3)2 + (y-2)2 = 3
C. (x+3)2 + (y-2)2 = 9
D. (x-3)2 + (y-2)2 = 3

The circle below is centered at 3 2 and has a radius of 3 What is its equation A x32 22 9 B x32 y22 3 C x32 y22 9 D x32 y22 3 class=

Respuesta :

763396

Answer:

C

Step-by-step explanation:

The equation is (x-a)^2 + (y-b)^2 = r^2

(x+3)^2+(y-2)^2 = 9

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