Probability of getting exactly 1 heads is 0.094.
As a binomial model, there are only two outcomes, the heads & tails
For a coin, the probability of getting heads or tails = 1 /2 = 0.5
Let 'X' be the no of heads obtained
Let :p" be the probability of getting heads
X~Bin (n=6, p = 0.5)
P (X=x) = [tex]nCx * p^{x}* (1-p)^{n-x}[/tex]
P (X=x) = [tex]6Cx* 0.5^{x} * (1-0.5)^{6-x}[/tex]
P (X=x) = [tex]6Cx* 0.5^{x} * (0.5)^{6-x}[/tex]
Note that we need to find probability of getting exactly 1 heads. So we will input the figures
P (X=1) = [tex]6C1 * 0.5^{1} * 0.5^{6-1}[/tex]
P (X=1) = [tex]6C1 * 0.5^{1} * 0.5^{5}[/tex]
P (X=1) = [tex]6 * 0.5 * 0.03125[/tex]
P (X=1) = 0.09375
P (X=1) = 0.094
Therefore, the probability of getting exactly 1 heads is 0.094.
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