The perimeter of a parallelogram must be no less than 40 feet. The length of the rectangle is 6 feet. What are the possible measurements of the width?

Write an inequality to represent this problem. Use w to represent the width of the parallelogram. [Hint: The formula for finding the perimeter of a parallelogram is $P=2l+2w.$
What is the smallest possible measurement of the width? Justify your answer by showing all your work.

If you know that your perimeter must be no less than 40 feet, you can say that P >= 40 ft. Since P is given by P=2l+2w, you can combine the two equations into a single inequality:

2l+2w >= 40

If the length is given by 6 feet, then you can further simplify the inequality to be

12+2w >= 40 --> w >=14

This means that the smallest possible measurement of the width is 14 feet.

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Аноним Аноним · Answer 2 · 2022-04-14T20:06:00+02:00

Answer:

12+2w>40

w > 19

A minimum value of w is 20ft.

Step-by-step explanation:

If the variable l is the length of the parallelogram, and w is its width, then the perimeter of the parallelogram will be,

P = 2l + 2w.

l = 6ft and P > 40ft.

Thus, 2(6) + 2w > 40

-> 12 + 2w > 40

This is the required inequality.

Now, 2w > 38

-> w > 19ft.

So currently, the smallest possible measurement of the width is 20ft.

Step-by-step explanation: