A triangle’s three sides are of lengths x meters, 2x meters, and 4x meters. If the perimeter of the triangle is 32 meters, find the lengths of the sides

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Answer:

32=x+2x+4x

32=7x

x=4.571428571428571428

and,2x=9.142857142857142857

and,4x=18.28571428571428571

Step-by-step explanation:

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Answer:

Lengths are 32/7, 64/7, and 128/7

I recommend seeing the explanation. I included the answers in decimal, how I got each answer, and which sides is for which expression

Step-by-step explanation:

A perimeter is the length of all sides and we know the perimeter of this triangle is 32 meters. It's given that the three sides of the triangle are x, 2x, and 4x, so if we add these sides together, we get 32

x + 2x + 4x = 32

We have to solve for x before we proceed to anything else

x + 2x + 4x = 32

Add like terms

7x = 32

Divide both sides by 7

x = 32/7 or 4.5714

Now that we have solved for x, we can now move on to find the sides. One of the sides is x meters and we already know x is equal to 32/7, so that is our answer.

To find 2x meters, we will have to multiply 2 by 32/7

2 * 32/7

We have to find a denominator for 2 that will both terms like fractions. 14/7 is the same as 2 so we will replace 2 with that (or you could find the LCM)

14/7 * 32/7 = 448/49

448 and 49 has a common factor of 7, so we will divide the numerator and denominator by 7

448 ÷ 7/49 ÷ 7 = 64/7

2x = 64/7 or 9.1428

To find 4x meters, we wil lhave to multiply 4 by 32/7

4 * 32/7

We will use the same method of making 4 into a fraction that is like terms with 32/7 (or find the LCM again)

28/7 * 32/7 = 896/49

896 and 49 has a common factor of 7, so we will divide the numerator and denominator by 7

896 ÷ 7/49 ÷ 7 = 128/7

4x = 128/7 or 18.2857