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easye2235

Answer:The solution contains 0.50 mol or 55 g of CaCl2 . You know there are 2.0 mol of CaCl2 in 1 L of solution. (40.08 + 2 × 35.45) g=(40.08 + 70.90)

g=110.98 g

Explanation:

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mahima6824soni

110.98 grams of CaCl₂ is there present in 2.0 M CaC₂.

What is calcium chloride?

Calcium chloride is made up of calcium and chloride.

Given, that the solution contain 250 mL of 2.0 M CaCl2

You know there are 2.0 mol of CaCl2 in 1 L of solution.

(40.08 + 2 × 35.45) g

= (40.08 + 70.90)

=110.98 g

Thus, 110.98 grams of CaCl₂ is there present in 2.0 M CaC₂.

Learn more about calcium chloride

https://brainly.com/question/15296925

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