Answer:
Part 1) The length of the terrace is [tex]15\ ft[/tex]
Part 2) The width of the terrace is [tex]6\ ft[/tex]
Part 3) The area of the terrace is [tex]90\ ft^{2}[/tex]
Step-by-step explanation:
we know that
The scale of the plan is [tex]\frac{2}{6} \frac{in}{ft}[/tex]
see the attached figure to better understand the problem
Step 1
Find the length of the terrace
we know that
The length of a terrace in the plan is equal to [tex]5\ in[/tex]
so
by proportion
Find the length of the terrace in the actual
[tex]\frac{2}{6} \frac{in}{ft}=\frac{5}{x} \frac{in}{ft}\\ \\x=6*5/2\\ \\x=15\ ft[/tex]
Step 2
Find the width of the terrace
we know that
The width of a terrace in the plan is equal to [tex]2\ in[/tex]
so
by proportion
Find the width of the terrace in the actual
[tex]\frac{2}{6} \frac{in}{ft}=\frac{2}{x} \frac{in}{ft}\\ \\x=6*2/2\\ \\x=6\ ft[/tex]
Step 3
Find the area of a terrace
we know that
The area of a terrace is equal to
[tex]A=LW[/tex]
we have
[tex]L=15\ ft[/tex]
[tex]W=6\ ft[/tex]
substitute
[tex]A=15*6=90\ ft^{2}[/tex]
