The baseball held 2 meters above the ground has more potential energy than the baseball held 1 meter above the ground.
The potential energy can be calculated with the following equation:
[tex] E_{p} = mgh [/tex]
Where:
m: is the mass of the baseball
g: is the acceleration due to gravity
h: is the height
We can see from equation (1) that the potential energy depends on height, mass, and gravity. Since the question refers to the same baseball, the mass is constant besides the acceleration due to gravity, so:
- Potential energy above 1 m
[tex] E_{p_{1}} = mg*1 = mg [/tex] (1)
- Potential energy above 2 m
[tex] E_{p_{2}} = mg*2 = 2mg [/tex] (2)
By entering equation (1) into 2 we have:
[tex] E_{p_{2}} = 2mg = 2E_{p_{1}} [/tex]
Hence, the potential energy of the baseball held 2 m above the ground is twice that of the baseball held 1 m above the ground.
Therefore, the baseball held 2 m above the ground has more potential energy.
You can learn more about potential energy here: https://brainly.com/question/15813853?referrer=searchResults
I hope it helps you!
