Answer: The molecular weight of tris buffer is 121 g/mol
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.
[tex]Molarity=\frac{n}{V_s}[/tex]
where,
n = moles of solute
[tex]V_s[/tex] = volume of solution in L
moles of tris buffer = [tex]\frac{\text {given mass}}{\text {Molar mass}}=\frac{12.1g}{Mg/mol}[/tex]
Now put all the given values in the formula of molality, we get
[tex]0.1=\frac{12.1g}{Mg/mol\times 1L}[/tex]
[tex]M=121g/mol[/tex]
Therefore, the molecular weight of tris buffer is 121 g/mol
