Answer:
Option D. 7.56 g of Hg.
Explanation:
The balanced equation for the reaction is given below:
4HgS + 4CaO —> 4Hg + 3CaS + CaSO₄
Next, we shall determine the mass of CaO that reacted and the mass of Hg produced from the balanced equation. This is can be obtained as follow:
Molar mass of CaO = 40 + 16
= 56 g/mol
Mass of CaO from the balanced equation = 4 × 56 = 224 g
Molar mass of Hg = 200.59 g/mol
Mass of Hg from the balanced equation = 4 × 200.59 = 802.36 g
SUMMARY
From the balanced equation above,
224 g of CaO reacted to produce 802.36 g of Hg.
Finally, we shall determine the mass of Hg produced by the reaction of 2.11 g of CaO. This can be obtained as follow:
From the balanced equation above,
224 g of CaO reacted to produce 802.36 g of Hg.
Therefore, 2.11 g of CaO will react to produce = (2.11 × 802.36)/224 = 7.56 g of Hg.
Thus, 7.56 g of Hg were obtained from the reaction.
