Answer: 31.9%
Explanation: sorry if the explanation is not that good because I am doing a assignment... but the answer is right
The percent by mass of water in copper(II) sulfate pentahydrate. CuSO4 5H20 will be 56.60% in the given complex compound.
Complex compounds are the types of the compound in inorganic chemistry that are attached to one central atom and others are the ligands attached to it the bond between them is made due to the formation of a coordinate bond
In copper(II) sulfate pentahydrate copper will be the central atom and hydrate molecules are ligands.
The percent by mass of water = [mass of H20 × 5 /mass of CuSO4 ] × 100
mass of CuSO4 = 149
mass of H20 × 5 = 90
substituting the value
The percent by mass of water = 90 / 149 × 100
The percentt by mass of water = 56.60%
Therefore, percent by mass of water in copper(II) sulfate pentahydrate. (CuSO45H20) will be 56.60% in the given complex compound.
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