Answer:
Q = 33105.6 J
Explanation:
Given that,
Mass of water, m = 88 grams
The temperature raised from 48°C to steam at 138°.
We need to find the energy required to raise the temperature. The formula for the energy required is given by :
[tex]Q=mc\Delta T[/tex]
Where
c is specific heat of water, c = 4.18J/g °C
So,
[tex]Q=88\times 4.18\times (138-48)\\\\Q=33105.6\ J[/tex]
So, the required energy is 33105.6 J.
