Answer:
The average value of the function on the interval [-1, 6] is [tex]2.\overline{1428571}[/tex]
Explanation:
The given
The average of a function is the height, 'h', of a rectangle with a width equivalent to the given interval and an area equivalent to the area of the function
The area under the graph of the function between the interval [-1, 6] consist of two right triangles and a rectangle and it is therefore given as follows;
The area. A = 1/2 × (0 - (-1)) × 2 + 2 × (6 - 0) + 1/2 × (4 - 2) × (6 - 4) = 15
The width of the rectangle, w = (6 - (-1)) = 7
w = 7
The area of the rectangle = h × w = A = 15
∴ The average value of the function, f = h = A/w = 15/7 = [tex]2.\overline{1428571}[/tex]
