After being rearranged and simplified, which two of the following equations
could be solved using the quadratic formula?
A. 5x2 – 3x+ 10 = 5x2
B. x2 - 6x- 7 = 2
C. 5x3 + 2x - 4 = 2x2
D. 5x2 - 3x + 10 = 2x2 + 21

Respuesta :

D because I simplified it and got a quadratic formula which also simplified as the answer D

The two equations could be solved using the quadratic formula are: B. [tex]x^2 - 6x- 7 = 2[/tex] and D. [tex]5x^2 - 3x + 10 = 2x^2 + 21[/tex]

What is equation?

"It is a mathematical statement which consists of equal symbol between two algebraic expressions."

What is quadratic equation?

"An equation of the form [tex]ax^{2} +bx+c=0[/tex] where a, b, and c are real numbers with a ≠ 0"

For given question,

The power of quadratic formula is always = 2

let's simplify and examine the given equations, and see if each can be solved with the quadratic formula:

A.

[tex]\Rightarrow 5x^2 - 3x+ 10 = 5x^2\\\\\Rightarrow 5x^2 - 3x+ 10 - 5x^2=5x^2-5x^2\\\\\Rightarrow -3x+10=0[/tex]

The degree of above equation is one,  so it could not be solved using the quadratic formula.

B.

[tex]\Rightarrow x^2 - 6x- 7 = 2\\\\\Rightarrow x^2 - 6x- 7 -2= 0\\\\ \Rightarrow x^2 - 6x- 9 = 0[/tex]

The degree of above equation is two, so it could be solved using the quadratic formula.

C.

[tex]\Rightarrow 5x^3 + 2x - 4 = 2x^2[/tex]

The degree of above equation is three, so it could not be solved using the quadratic formula.

D.

[tex]\Rightarrow 5x^2 - 3x + 10 = 2x^2 + 21\\\\\Rightarrow 5x^2 - 3x + 10 - 2x^2 - 21=0\\\\\Rightarrow 3x^2-3x-11=0[/tex]

The degree of above equation is two, so it could be solved using the quadratic formula.

Therefore, the two equations could be solved using the quadratic formula are: B. [tex]x^2 - 6x- 7 = 2[/tex] and D. [tex]5x^2 - 3x + 10 = 2x^2 + 21[/tex]

Learn more about quadratic formula here:

https://brainly.com/question/2615966

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