Answer:
the final velocity of the train is -4.99 m/s.
Explanation:
Given;
initial velocity of the train, u = -0.4 m/s
acceleration of the train, a = -0.27 m/s²
time of motion of the train, t = 17 s
The final velocity of the train is calculated as follows;
v = u + at
where;
v is the final velocity of the train
v = -0.4 + (-0.27 x 17)
v = -0.4 - 4.59
v = -4.99 m/s
Therefore, the final velocity of the train is -4.99 m/s.
