Jabal walks at a rate of 2.5 meters per second (m/s).
Michael walks at a rate of 2 meters per second (m/s).
They both leave their houses at the same time to walk to school.
They walk down the same street in the same direction.
Michael's house is 100 meters closer to school than Jabal's house.

Objective: Solve distance problems by creating and solving a linear ... To find the total distance we would multiply rate times time or (30)(4) = 120. ... We only know they both start and end at the same ... Bob and Fred start from the same point and walk in opposite directions. ... Mike leaves his house traveling 2 miles per hour.

Step-by-step explanation:

Answer Link

Jabal walks at a rate of 2.5 meters per second (m/s). Michael walks at a rate of 2 meters per second (m/s). They both leave their houses at the same time to walk to school. They walk down the same street in the same direction. Michael's house is 100 meters closer to school than Jabal's house.

Respuesta :

Otras preguntas

Jabal walks at a rate of 2.5 meters per second (m/s).
Michael walks at a rate of 2 meters per second (m/s).
They both leave their houses at the same time to walk to school.
They walk down the same street in the same direction.
Michael's house is 100 meters closer to school than Jabal's house.