The distance between points (-7, 8) and (2, 8) is 9 units.
The distance d between two points [tex](x_{1},y_{1}),(x_{2},y_{2})[/tex] is,[tex]d=\sqrt{(x_{2}-x_{1})^{2}+ (y_{2}-y_{1})^{2} }[/tex]
For given question,
Let [tex](x_{1},y_{1}) = (-7,8),(x_{2},y_{2})=(2,8)[/tex]
Let d be the distance between two points.
Using distance formula,
[tex]d=\sqrt{(x_{2}-x_{1})^{2}+ (y_{2}-y_{1})^{2}[/tex]
[tex]d=\sqrt{(2-(-7))^{2}+ (8-8)^{2} }[/tex]
[tex]d=\sqrt{(2+7)^{2}+0^{2}[/tex]
[tex]d=\sqrt{9^{2}+0 }[/tex]
[tex]d=9[/tex] units
Hence, the distance between points (-7, 8) and (2, 8) is 9 units.
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