Answer: 30.72 moles of [tex]CO_2[/tex] will be produced from 5.12 moles of glucose.
Explanation:
The balanced chemical equation for combustion of glucose is:
[tex]C_6H_{12}O_6+6O_2\rightarrow 6CO_2+6H_2O[/tex]
According to stoichiometry :
1 moles of glucose produce = 6 moles of [tex]CO_2[/tex]
Thus 5.12 moles of glucose produce =[tex]\frac{6}{1}\times 5.12=30.72moles[/tex] of [tex]CO_2[/tex]
Thus 30.72 moles of [tex]CO_2[/tex] will be produced from 5.12 moles of glucose.
