Answer:
V = 5.97 L
Explanation:
Hello!
In this case, according to the ideal gas law:
[tex]PV=nRT[/tex]
We would need to solve for V as we know the temperature and pressure as the gas it at STP conditions (273 K and 1 atm respectively):
[tex]V=\frac{nRT}{P}[/tex]
Next, we compute the moles in 8 g of NO, given its molar mass of 30.01 g/mol:
[tex]n=\frac{8g}{30.01g/mol}=0.267mol[/tex]
Therefore, we obtain the following volume:
[tex]V=\frac{0.267mol*0.08206\frac{atm*L}{mol*K}*273K}{1atm}\\\\V=5.97 L[/tex]
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