Answer:
21 Kg of CO.
Explanation:
The balanced equation for the reaction is given below:
Fe₂O₃ + 3CO —> 2Fe + 3CO₂
Next, we shall determine the masses of Fe₂O₃ and CO that reacted from the balanced equation. This can be obtained as illustrated below:
Molar mass of Fe₂O₃ = (56×2) + (16×3)
= 112 + 48
= 160 g/mol
Mass of Fe₂O₃ from the balanced equation = 1 × 160 = 160 g
Molar mass of CO = 12 + 16 = 28 g/mol
Mass of CO from the balanced equation = 3 × 28 = 84 g
SUMMARY:
From the balanced equation above,
160 g Fe₂O₃ required 84 g of CO.
Finally, we shall determine the mass of of CO required for the reduction of 40 kg of Fe₂O₃. This can be obtained as follow:
From the balanced equation above,
160 g Fe₂O₃ required 84 g of CO.
Therefore, 40 Kg of Fe₂O₃ will require = (40 kg × 84 g) / 160 g = 21 Kg of CO.
Thus, 21 Kg of CO is required for the reaction.
