Answer:
[tex]\alpha = 4.44 * 10^{-5} ^\circ C^{-1}[/tex]
Explanation:
Given
[tex]L_1 = 15.01m[/tex]
[tex]L_2 = 15.05m[/tex]
[tex]\triangle T = 60^\circ C[/tex]
Required
Determine its linear expansivity
This is calculated as:
[tex]\alpha = \frac{L_2 - L_1}{\triangle T * L1}[/tex]
[tex]\alpha = \frac{15.05m - 15.01m}{60^\circ C* 15.01m}[/tex]
[tex]\alpha = \frac{0.04m}{60^\circ C * 15.01m}[/tex]
[tex]\alpha = \frac{0.04}{60^\circ C* 15.01}[/tex]
[tex]\alpha = \frac{0.04}{900.6^\circ C}[/tex]
[tex]\alpha = 0.00004441483^\circ C^{-1}[/tex]
[tex]\alpha = 4.441483 * 10^{-5} ^\circ C^{-1}[/tex]
[tex]\alpha = 4.44 * 10^{-5} ^\circ C^{-1}[/tex]
