Mr. Ammons is constructing a walkway through his rectangular Garden. The walkway runs diagonally as shown in the diagram. Which is closest to the length of the walkway?​

Mr Ammons is constructing a walkway through his rectangular Garden The walkway runs diagonally as shown in the diagram Which is closest to the length of the wal class=

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Answer:

your answer will be Option B. 28.3 ft

Step-by-step explanation:

[tex] \sqrt{15 ^{2} } + 24 ^{2} = 28.3[/tex] or

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The 28.3 ft is closest to the length of the walkway. the answer will be Option B. 28.3 ft

What is Pythagoras Theorem?

If ABC is a triangle with AC as the hypotenuse and angle B with 90 degrees then we have:

|AC|^2 = |AB|^2 + |BC|^2    

where |AB| = length of line segment AB. (AB and BC are rest of the two sides of that triangle ABC, AC being the hypotenuse).

It is given that Mr. Ammons is constructing a walkway through his rectangular Garden. The walkway runs diagonally as shown in the diagram.

We need to find the length of the walkway.

Using Pythagoras Theorem;

[tex]15^2 + 24^2 = x^{2} \\\\x^{2} = 225 + 576\\\\x^{2} = 801\\\\x = \sqrt{801} \\\\x = 28.30[/tex]

Therefore, 28.3 ft is closest to the length of the walkway. answer will be Option B. 28.3 ft

Learn more about Pythagoras theorem here:

https://brainly.com/question/12105522

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