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A particular fruit's weights are normally distributed, with a mean of 372 grams and a standard deviation of 26 grams. If you pick 36 fruit at random, what is the probability that their mean weight will be between 365 grams and 380 grams

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valerieramirez888

Answer: 90.93%

Step-by-step explanation:

M= 372

s= 26

n=36

P(365<x<380)

1. Find Z ----> 365-372 [tex]\sqrt{36}[/tex] = -1.6     Next Z---->  380 - 372 [tex]\sqrt{36}[/tex]=  1.8

                           26                                               26

2.  plug into calculator to find probablity: normalcdf(-1.6 , 1.8 ) = .90927 or 90.93% that the prob is between 365 and 380

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