Answer:
0.48 = 48% probability that an employee selected at random will need either corrective shoes or major dental work
Step-by-step explanation:
I am going to solve this question treating these events as Venn probabilities.
I am going to say that:
Event A: Employee needed corrective shoes.
Event B: Employee needed major dental work.
22% of the employees needed corrective shoes
This means that [tex]P(A) = 0.22[/tex]
29% needed major dental work
This means that [tex]P(B) = 0.29[/tex]
3% needed both corrective shoes and major dental work.
This means that [tex]P(A \cap B) = 0.03[/tex]
What is the probability that an employee selected at random will need either corrective shoes or major dental work?
This is:
[tex]P(A \cup B) = P(A) + P(B) - P(A \cap B)[/tex]
Replacing the values that we have:
[tex]P(A \cup B) = 0.22 + 0.29 - 0.03 = 0.48[/tex]
0.48 = 48% probability that an employee selected at random will need either corrective shoes or major dental work
