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If a wave has a speed of 362 m/s and a period of 4.17 ms, its wavelength is closest to
O A. 1.51 m
B.0.0115 m
OC. 86.8 m
OD. 1510 m

Respuesta :

Cricetus

Answer:

Option A (1.51 m) is the appropriate option.

Explanation:

The given values are:

Speed of wave,

= 362 m/s

Period,

= 4.17

Now,

⇒  [tex]v=\frac{\lambda}{T}[/tex]

then,

⇒  [tex]\lambda=vT[/tex]

⇒     [tex]= 362\times 4.17\times 10^{-3}[/tex]

⇒     [tex]=1.51 \ m[/tex]

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