Answer:
17.0 g
Explanation:
Step 1: Write the reaction for the decomposition of ammonia
2 NH₃(g) ⇒ N₂(g) + 3 H₂(g)
Step 2: Calculate the moles corresponding to 95.7 g of NH₃
The molar mass of NH₃ is 17.03 g/mol.
95.7 g × 1 mol/17.03 g = 5.62 mol
Step 3: Calculate the moles of H₂ produced from 5.62 moles of NH₃
The molar ratio of NH₃ to H₂ is 2:3. The moles of H₂ produced are 3/2 × 5.62 mol = 8.43 mol.
Step 4: Calculate the mass corresponding to 8.43 moles of H₂
The molar mass of H₂ is 2.02 g/mol.
8.43 mol × 2.02 g/mol = 17.0 g
