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A chemical reaction is expected to produce 0.068 moles of oxygen. What volume in liters will be occupied by this gas sample at 273K and 1 atm?​

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Answer: 1.22 litres

Explanation: in STP conditions amount of substance n= V/Vm

Vm is molar volume of gas, 22.41 litres/ mole.

Volume V = n·Vm= 0.068 mol·22.41 l / mol= 1.52388 litres

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