Answer:
See explanation
Explanation:
The equation of the reaction is;
2H3PO4(aq) + 3Ca(OH)2(aq) --------->Ca3(PO4)2(aq) + 6H2O(l)
a) From the reaction equation;
2 moles of H3PO4 reacts with 3 moles of Ca(OH)2
16.5 moles of H3PO4 reacts with 16.5 * 3/2 = 24.75 moles of Ca(OH)2
Mass = 24.75 moles of Ca(OH)2 * 74.093 g/mol
Mass = 1833.8 g of Ca(OH)2
b) if 1 mole of Ca(OH)2 = 6.02 * 10^23 molecules
x moles of Ca(OH)2 = 5.06 * 10^24 molecules
x = 5.06 * 10^24 molecules * 1 mole/6.02 * 10^23 molecules
x = 8.4 moles
3 moles of Ca(OH)2 produces 6 moles of H2O
8.4 moles of Ca(OH)2 yields x moles of H2O
x = 8.4 * 6/3
x = 16.8 moles of H20
1 mole of H2O = 6.02 * 10^23 molecules
16.8 moles of H20 = 16.8 moles * 6.02 * 10^23 molecules/ 1 mole
= 1.01 * 10^25 molecules of H2O
c) since 1 mole of Ca3(PO4)2 occupies 22.4 L and only 1 mole of Ca3(PO4)2 is produced in the reaction so;
22.4 L is occupied by Ca3(PO4)2 when 6(22.4) L of water is produced
x litres of Ca3(PO4)2 is occupied when 4.2 L of water is produced
x = 22.4 L * 4.2 L/ 6(22.4) L
x = 0.7 L of Ca3(PO4)2
