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What is the initial temperature (in Celsius) of a 675 ml balloon if the
temperature increases to 45 °C and the volume changes to 1900 mL

Respuesta :

allenjmathew2121

Answer: 127 (3.s.f)

Explanation:

Boyle's law states that Volume x pressure = constant

Therefore let's first find the constant: 45 x 1900 = 85500

Then lets plug 675 ml and 85500 into the equation above:

675 x C = 85500

C = 127 (3 s.f.)

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