Question:
Because of a problem in the program, the timer in a video player did not begin counting until the video had been playing for several seconds. The player began counting at 0 seconds, even though the video had already played 190 frames. The video plays 25 frames per second.
How many frames had the video already played when the time was equal to [tex]3\dfrac{2}{5}[/tex]
Answer:
275 frames
Step-by-step explanation:
Given
[tex]Start\ time = 0s[/tex]
[tex]Rate =25frames/sec[/tex]
[tex]Played = 190\ frames[/tex]
Required
Number of frames played when [tex]time = 3\frac{2}{5}[/tex]
First, calculate the time taken to play 190 frames
[tex]Time = \frac{Frames}{Rate}[/tex]
[tex]Time = \frac{190}{25}[/tex]
[tex]Time = 7\frac{3}{5}[/tex]
So, when the time is at: [tex]3\frac{2}{5}[/tex]
The total time is:
[tex]Total = 7\frac{3}{5} + 3\frac{2}{5} -0[/tex]
[tex]Total =\frac{38}{5} + \frac{17}{5}[/tex]
Take LCM
[tex]Total =\frac{38+17}{5}[/tex]
[tex]Total =\frac{55}{5}[/tex]
[tex]Total =11s[/tex]
The number of frames is then calculated as:
[tex]Frames = Rate * Time[/tex]
[tex]Frames = 25 * 11[/tex]
[tex]Frames = 275[/tex]
