Answer:
The work done is 4386.6 J.
Step-by-step explanation:
The work is given by:
[tex] W = Fd [/tex]
Where:
F: is the applied force = 42 pounds
d: is the displacement = 85 feet
Since the force is applied at an angle (θ) of 25° with the horizontal we have:
[tex] W = Fcos(\theta)d [/tex]
[tex] W = 42 lb*\frac{4.448 N}{1 lb}cos(25)*85 ft*\frac{0.3048 m}{1 ft} = 4386.6 J [/tex]
Therefore, the work done is 4386.6 J.
I hope it helps you!
