Answer:
[tex]-2.5\ \text{m/s}^2[/tex]
[tex]-5500\ \text{N}[/tex]
Explanation:
m = Mass of car = 2200 kg
t = Time = 10 s
v = Final velocity = 0
u = Initial velocity = 25 m/s
a = Acceleration
From the kinematic equations of linear motion we have
[tex]v=u+at\\\Rightarrow a=\dfrac{v-u}{t}\\\Rightarrow a=\dfrac{0-25}{10}\\\Rightarrow a=-2.5\ \text{m/s}^2[/tex]
Acceleration of the car is [tex]-2.5\ \text{m/s}^2[/tex]
Force is given by
[tex]F=ma\\\Rightarrow F=2200\times (-2.5)\\\Rightarrow F=-5500\ \text{N}[/tex]
Net force required to produce the acceleration is [tex]-5500\ \text{N}[/tex].
