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In ΔBCD, the measure of ∠D=90°, the measure of ∠B=22°, and DB = 44 feet. Find the length of BC to the nearest tenth of a foot.

In ΔBCD the measure of D90 the measure of B22 and DB 44 feet Find the length of BC to the nearest tenth of a foot class=

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Answer: 47.5 ft

Step-by-step explanation:

since this is a right triangle, you can use trig to solve for x:

cos 22° = [tex]\frac{44}{x}[/tex] (cos = adjacent/hypotenuse)

x * cos 22° = 44

x = [tex]\frac{44}{cos 22}[/tex] (plug into calc)

x = 47.5 ft

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