contestada

488 nm light passes through a single
slit. The first (m = 1) diffraction
minimum occurs at an angle of
0.559º. What is the width of the slit?
[?] x 10-5 m

488 nm light passes through a single slit The first m 1 diffraction minimum occurs at an angle of 0559º What is the width of the slit x 105 m class=

Respuesta :

Answer:

5.00

Explanation:

a sinθ=mλ

You are missing (a) so you move sinθ to the other side than solve from there.

For first diffraction, the width of the slit is [tex]5*10^{-5} m[/tex].

What is diffraction?

Diffraction of light is defined as the bending of light around corners such that it spreads out and illuminates areas where a shadow is expected.

a sinθ=mλ

[tex]a = \frac{1*488*10^{-9} }{sin 0.559}[/tex]

[tex]a = 5*10^{-5} m[/tex]

To learn more about Diffraction here

https://brainly.com/question/16096548

#SPJ2

Otras preguntas