Answer:
a)
Explanation:
From the given information:
The avg diameters:
For P1 grapes =1.2 cm
For P2 grapes = 1.6 cm
Their vairance is also given as follows:
For P1 = 0.30 cm²
For P2 = 0.56 cm²
Recall that:
the phenotypic variance VP = genetic variance (VG) + environmental variance VE
As stated that P1 and P2 lines are pure breeding lines, which means that the diameter of the seed in F1 was around halfway between the two parents' and the difference in the F1 was close to the parents'.
This implies that, provided the parent lines exist as pure breeding;
The genetic variation would be absent, indicating that VG is zero.
∴
VP = VE and VG = 0
Now, averaging the results of two pure breeding lines, we have:
[tex]V_E = \Big (\dfrac{0.30 + 0.56}{2} \Big) \\ \\ V_E = \dfrac{0.86}{2} \\ \\ V_E = 0.43 \ cm^2[/tex]
The formula used in estimating F1 genetic variance can be expressed as:
VP = VG + VE
Recall that
VE = VP = 0.43 cm²
∴
0.43 = VG + 0.43
VG = 0.43 - 0.43
VG = 0
Thus, The statement that is false is in Option a.
VG for F1 is > 0
