Answer:
√5 + √36
√9 + √24
3√12
These are radicals
Step-by-step explanation:
[tex]\sqrt{4}+\sqrt{16}=\sqrt{2*2}+\sqrt{4*4}=2+4 = 6[/tex]
Not radical
[tex]\sqrt{5}+\sqrt{36}=\sqrt{5}+\sqrt{6*6}=\sqrt{5}+6[/tex]
It is a radical
[tex]\sqrt{9}+\sqrt{24}=\sqrt{3*3}+\sqrt{2*2*2*3}=3+2\sqrt{2*3}=2+2\sqrt{6}[/tex]
It is radical
[tex]2*\sqrt{4}=2*2=4[/tex]
Not radical
[tex]\sqrt{49}*\sqrt{81}=\sqrt{7*7}*\sqrt{9*9}=7*9=63[/tex]
Not radical
[tex]3\sqrt{12}=3\sqrt{2*2*3}=2\sqrt{3}[/tex]
Radical
