Graph the function. f(x)=2x^2-5
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Аноним Аноним · Answer 1 · 2021-05-02T03:58:36+02:00

f(x)=2x^2+0x-5

Find the vertex

0/4=0=x

Input x into the equation to find y or f(x)

0+0-5=f(x)

(0,-5) = Vertex

Now find a random x coordinate to input into the equation.

Let's do 4.

32+0-5=f(x)=27

It may not look like a parabola due to it being uneven.

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ayoushivt ayoushivt · Answer 2 · 2022-07-16T12:01:57+02:00

The graph of the function that represents a vertical parabola with vertex at ( 0 , -5) has been plotted and attached with the answer.

A function is a law that links two variables , a dependent and an independent variable .

The given function is

f(x) = 2x² - 5

y = a( x-h)² +k

this is an equation of a vertical parabola

(h,k) is the vertex

here ( 0 , -5) is the vertex

The graph of the function has been plotted and attached with the answer.

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