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A child has a toy balloon with a volume of 1.75 liters. The temperature of the
balloon when it was filled was 21° C and the pressure was 1.00 atm. If the child
were to let go of the balloon and it rose 3 kilometers into the sky where the
pressure is 0.65 atm and the temperature is -10°C, what would the new volume
of the balloon be?

Respuesta :

samueladesida43

Answer:

2.41 Litres

Explanation:

Using the combined gas law equation as follows;

P1V1/T1 = P2V2/T2

Where;

P1 = initial pressure (atm)

P2 = final pressure (atm)

V1 = initial volume (L)

V2 = final volume (L)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the information provided in this question;

P1 = 1 atm

P2 = 0.65 atm

V1 = 1.75 liters

V2 = ?

T1 = 21°C = 21 + 273 = 294 K

T2 = -10°C = -10 + 273 = 263 K

Using P1V1/T1 = P2V2/T2

1 × 1.75/294 = 0.65 × V2/263

1.75/294 = 0.65V2/263

Cross multiply

294 × 0.65V2 = 1.75 × 263

191.1 V2 = 460.25

V2 = 460.25 ÷ 191.1

V2 = 2.41 L

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