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9. A plastic pipe 10 cm long has an
outside diameter of 5 cm and an
inside diameter of 4 cm. If the
density of the plastic is 0.92 g/cm3,
what is the mass of the pipe? Use
3.14 for a, and round your answer
to the nearest gram.

Respuesta :

First find the volume of the pipe:

V = 3.14*length*(outsideradius^2 - innerradius^2)
= 3.14 * 10*(2.5^2 - 2^2)
= 70.65 cm^3

Now find the mass using the formula density = mass / volume:

Mass = volume * density
= 70.65 cm^3 * 0.92g/cm^3
= 65 grams

The mass of the plastic pipe which is 10 cm long and has an outside diameter of 5 cm and an inside diameter of 4 cm is 65 grams.

What is of volume of a hollow cylinder?

Volume of a hollow cylinder is the amount of quantity, which is obtained by it in the 3 dimensional space.

The volume of hollow cylinder can be given as,

[tex]V=\pi (r_2^2-r_1^2)h[/tex]

Here, (r₂) is the outer radius of the cylinder, (r₁) is the inner radius of the cylinder and (h) is the height of the cylinder.

A plastic pipe 10 cm long has an outside diameter of 5 cm and an inside diameter of 4 cm. Radius is half of the diameter. Thus, the outer radius is 2.5 cm (5/2) and the inner radius is 2 cm (4/2).

The volume of this cylinder is,

[tex]V=3.14 ((2.5)^2-2^2)\times10\\V=70.65\rm\; cm^3[/tex]

The mass of plastic pipe is the product of its volume and density. The density of the plastic is 0.92 g/cm3. Thus, the mass of it is,

[tex]m=70.65\times0.92\\m=65\rm\; grams[/tex]

Thus, the mass of the plastic pipe which is 10 cm long and has an outside diameter of 5 cm and an inside diameter of 4 cm is 65 grams.

Learn more about the volume of cylinder here;

https://brainly.com/question/12748872

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