Answer:
9) 3.7 in
10) 12 in²
11) 18 in³
12) V=432π cm³
TSA= 216π cm²
13)V=448π ft³
TSA=240π ft²
Step-by-step explanation:
9) Since all side of the trapezium are the same the height = perpendicular line which is 3.7 in
10) 3×4 (the quadrilateral at the bottom)
11)∵ A= Cross-sectional area× height
⇒A= Area of the trapezium × 4
∴ A=[tex]\frac{1}{2} \\[/tex] (sum of the parallel sides) × 4
A=[tex]\frac{1}{2} \\[/tex] (3+6) × 4
A= 18 in²
12) V=πr²h
V=π(6)²(12)
⇒V=432 cm³
TSA=2(πr²)+2πrh
TSA=2(π(6)²)+2π(6)(12)
⇒TSA=240π cm²
13. V=πr²h
V=π(8)²(7)
V=448π ft³
TSA=2(πr²)+2πrh
TSA=2(π(8)²)+2π(8)(7)
TSA=240π ft²
