A laboratory technician needs to make a 72-liter batch of a 20% acid solution. How can the laboratory technician combine a batch of an acid solution that is pure acid with another that is 10% to get the desired concentration?

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Аноним Аноним · Answer 1 · 2016-12-01T01:32:38+01:00

I hope this helps you 72.20%=(72+?).10% 72.2=72+? ?=72

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kobenhavn kobenhavn · Answer 2 · 2019-10-22T12:25:08+02:00

Answer: 8 L of 100% pure acid and 64 L of 10% acid must be combined

Step-by-step explanation:

According to the dilution law,

[tex]C_1V_1+C_2V_2=C_3V_3[/tex]

where,

[tex]C_1[/tex] = concentration of pure acid solution = 100 %

[tex]V_1[/tex] = volume of pure acid solution = x L

[tex]C_2[/tex] = concentration of another acid solution= 10%

[tex]V_2[/tex] = volume of another acid solution= (72-x) L

[tex]C_3[/tex] = concentration of resulting acid solution = 20 %

[tex]V_1[/tex] = volume of resulting acid solution = 72 L

Putting the values in the equation:

[tex]100\times x+10\times (72-x)=20\times 72[/tex]

[tex]x=8L[/tex]

Therefore, the laboratory technician must take 8 L of 100% pure acid and (72-8) = 64 L of 10% acid to get 72-liter batch of a 20% acid solution.