Be sure to answer all parts. The net reproductive rate, R0, of a population can be used to predict whether a population will grow or shrink over time. If R0 is greater than 1 then a population is growing; if it is less than 1, the population is shrinking; and if it is equal to one, then the population is at equilibrium. The size of the next generation (Nt 1) of a population can be determined by multiplying the net reproductive rate by the current population size, N. Part 1 out of 2 Given a current population size of 788 and a net reproductive rate of 1.00, what would be the size of the population in the next generation

There are some parameters to consider when analyzing the evolution of a population in time regarding its size. Some of them are the generational time -T-, the intrinsic growth rate per capita -r₀-, the net reproductive rate -R₀-, the reproductive value -V₀-. among others.

To obtain the net reproductive rate -R₀- of a population, we must relate the contribution of individuals of each age to the next generation, with the possibility that those individuals reach that age.

It can also be considered the media of female offspring that each female can produce throughout its whole life.

You can also think about it as a quantity by which the population abundance will increase, decrease, or remain the same in the followings generations. And this concept is related to what is stated in the problem.

If R₀>1 ⇒ the population size increases
If R₀<1 ⇒ the population size decreases
If R₀=1 ⇒ the population is in equilibrium. Its size remains the same.

According to the given information, we can use different formulas to calculate R₀

R₀ = N(t) / N(0) ------> (N0 being the population size at time zero, and Nt in a

certain generation)

R₀ = sum (lx * mx)---> (Lx being the survival rate and mx the fertility rate)

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To answer this question, instead of calculating the R₀ value, we need to calculate Nt, which is the population size at t generation. In this example, is the following generation, so t=1.

We already know that N₀ = 788 individuals and that R₀=1.

By clearing the equation R₀ = N(t) / N(0), we can get the Nt value.

N (t) = N₀ x R₀

N(t) = 788 x 1

N(t) = 788 individuals

The population size at time 0 and time 1 is the same. This is because the R₀ value = 1, meaning that the population is in equilibrium. It does not increase either decrease. Probably there are as many deaths as births.